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Solve the equation: X3- 5X-5 = 0. This equation cannot be factorised nor solved algebraically therefore it must be solved through interval bisection.  

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Interval Bisection. Ben Ward Solve the equation: X3- 5X-5 = 0. This equation cannot be factorised nor solved algebraically therefore it must be solved through interval bisection. To calculate the approximate position of the roots and the number of roots I used Omnigraph to sketch the graph (below shows where the graph crosses the x-axis). This is the root I want to find and shows how the solution lies between 2.6 and 2.7 [f (X) = X3 - 5X - 5] X0 = 2.6 f (X0) = -0.424 X1 = 2.7 f (X1) = + 1.183 As f(X0) <0 and f(X1)> 0 it shows that the solution must lie between X0 and X1, thus creating an error bound 2.6

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