Solve the equation: X3- 5X-5 = 0. This equation cannot be factorised nor solved algebraically therefore it must be solved through interval bisection.
Member rating:
(3 votes)
| Words:
| Submitted: Fri Aug 22 2003
On the left is an image preview of every page of this document, and below are the first 150 words with formatting removed:
Interval Bisection.
Ben Ward
Solve the equation: X3- 5X-5 = 0. This equation cannot be factorised nor solved algebraically therefore it must be solved through interval bisection.
To calculate the approximate position of the roots and the number of roots I used Omnigraph to sketch the graph (below shows where the graph crosses the x-axis).
This is the root I want to find and shows how the solution lies between 2.6 and 2.7
[f (X) = X3 - 5X - 5]
X0 = 2.6 f (X0) = -0.424
X1 = 2.7 f (X1) = + 1.183
As f(X0) <0 and f(X1)> 0 it shows that the solution must lie between X0 and X1, thus creating an error bound 2.6


