Maths Coursework: Curve Fitting
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| Submitted: Sun Dec 15 2002
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Maths Coursework: Curve Fitting I was firstly given the task of finding the equation of the quadratic graph which passes through the points (5,0), (3,0), (0,15). To solve this I began by drawing a rough sketch of what I thought the graph would look like with these points, as below: (0,15) (3,0) (5,0) I worked out that the graph would look like this, and next I worked out the formula by putting the numbers I knew into brackets, and then expanding them as below. I did this because by looking at the graph you can see that when Y=0, X=5 or X=3. Y = (x-5)(x-3) = 0 * x2-3x-5x+15 * =x2-8x+15 I worked the equation out to be Y=x2-8x+15. I then plotted this graph using omnigraph as below: I then went onto the second task of finding the equation of the quadratic graph which passes through (0,9) and touches the x-axis at (3,0). I used the same method as...


