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ANALYSIS: Method 1: Measure the volume of hydrogen produced when a known mass of lithium reacts with water. Set up apparatus. 250cm³ conical flask must contain 100cm³ of distilled water. Weigh between 0.08g and 0.13g of lithium. Record the exact mass of lithium. Remove the stopper, add lithium to the flask and quickly replace stopper. Collect the gas and record final volume of hydrogen. RESULTS: I used 0.08g of lithium, this produced 168cm³ of hydrogen gas. Treatment of results: Assuming that 1 mole of gas occupies 24,000cm3 at room temperature and pressure Calculating the number of moles of hydrogen: 168 / 24000 = 0.007 mol Number of moles of lithium: 0.007 x 2 = 0.014 mol Using above info and original mass of lithium, RAM of lithium can be calculated as: 1 / 0.014 x 0.08 = 5.7142 Method 2: Titration of aqueous LiOH with 0.100 mol dm HCl. 1 2 3 4 23.3 cm³ 22.7 cm³ 21.2 cm³ 22.9 cm³ Mean titre is: (22.7 + 22.9) / 2 = 22.8 On average, 25.0 cm of LiOH...

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